JavaAlgorithms/Maths/KeithNumber.java

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Java
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import java.util.*;
class KeithNumber
{
//user-defined function that checks if the given number is Keith or not
static boolean isKeith(int x)
{
//List stores all the digits of the X
ArrayList<Integer> terms=new ArrayList<Integer>();
//n denotes the number of digits
int temp = x, n = 0;
//executes until the condition becomes false
while (temp > 0)
{
//determines the last digit of the number and add it to the List
terms.add(temp%10);
//removes the last digit
temp = temp/10;
//increments the number of digits (n) by 1
n++;
}
//reverse the List
Collections.reverse(terms);
int next_term = 0, i = n;
//finds next term for the series
//loop executes until the condition returns true
while (next_term < x)
{
next_term = 0;
//next term is the sum of previous n terms (it depends on number of digits the number has)
for (int j=1; j<=n; j++)
next_term = next_term + terms.get(i-j);
terms.add(next_term);
i++;
}
//when the control comes out of the while loop, there will be two conditions:
//either next_term will be equal to x or greater than x
//if equal, the given number is Keith, else not
return (next_term == x);
}
//driver code
public static void main(String[] args)
{
Scanner in = new Scanner(System.in);
int n = in.nextInt();
if (isKeith(n))
System.out.println("Yes, the given number is a Keith number.");
else
System.out.println("No, the given number is not a Keith number.");
}
}