Merge pull request #468 from bansalKeshav/master
Add method for minimum number of coins required for given amount
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0b5c86e3a4
@ -10,9 +10,11 @@ public class CoinChange {
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public static void main(String[] args) {
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int amount = 12;
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int[] coins = {1, 2, 5};
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int[] coins = {2, 4, 5};
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System.out.println("Number of combinations of getting change for " + amount + " is: " + change(coins, amount));
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System.out.println("Minimum number of coins required for amount :" + amount + " is: " + minimumCoins(coins, amount));
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}
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/**
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@ -29,7 +31,7 @@ public class CoinChange {
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for (int coin : coins) {
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for (int i=coin; i<amount+1; i++) {
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combinations[i] += combinations[i-coin];
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combinations[i] += combinations[i-coin];
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}
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// Uncomment the below line to see the state of combinations for each coin
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// printAmount(combinations);
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@ -37,14 +39,41 @@ public class CoinChange {
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return combinations[amount];
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}
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/**
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* This method finds the minimum number of coins needed for a given amount.
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*
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* @param coins The list of coins
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* @param amount The amount for which we need to find the minimum number of coins.
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* Finds the the minimum number of coins that make a given value.
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**/
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public static int minimumCoins(int[] coins, int amount) {
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//minimumCoins[i] will store the minimum coins needed for amount i
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int[] minimumCoins = new int[amount+1];
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minimumCoins[0] = 0;
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for(int i=1;i<=amount;i++){
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minimumCoins[i]=Integer.MAX_VALUE;
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}
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for(int i=1;i<=amount;i++){
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for (int coin :coins){
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if(coin <=i){
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int sub_res = minimumCoins[i-coin];
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if (sub_res != Integer.MAX_VALUE && sub_res + 1 < minimumCoins[i])
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minimumCoins[i] = sub_res + 1;
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}
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}
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}
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// Uncomment the below line to see the state of combinations for each coin
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//printAmount(minimumCoins);
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return minimumCoins[amount];
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}
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// A basic print method which prints all the contents of the array
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public static void printAmount(int[] arr) {
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for (int i=0; i<arr.length; i++) {
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System.out.print(arr[i] + " ");
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}
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System.out.println();
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}
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}
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}
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