* fix doc

* add test
* fix armstrong number
This commit is contained in:
shellhub 2020-08-12 22:04:20 +08:00
parent 3cb9adfc6f
commit 2bd49e4728

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@ -1,49 +1,43 @@
package Others;
import java.util.Scanner;
/**
* A utility to check if a given number is armstrong or not. Armstrong number is
* a number that is equal to the sum of cubes of its digits for example 0, 1,
* 153, 370, 371, 407 etc. For example 153 = 1^3 + 5^3 +3^3
*
* @author mani manasa mylavarapu
* An Armstrong number is equal to the sum of the cubes of its digits.
* For example, 370 is an Armstrong number because 3*3*3 + 7*7*7 + 0*0*0 = 370.
* An Armstrong number is often called Narcissistic number.
*/
public class Armstrong {
static Scanner scan;
public static void main(String[] args) {
scan = new Scanner(System.in);
int n = inputInt("please enter the number");
boolean isArmstrong = checkIfANumberIsAmstrongOrNot(n);
if (isArmstrong) {
System.out.println("the number is armstrong");
} else {
System.out.println("the number is not armstrong");
}
assert (isArmStrong(0));
assert (isArmStrong(1));
assert (isArmStrong(153));
assert (isArmStrong(1634));
assert (isArmStrong(371));
assert (!isArmStrong(200));
}
/**
* Checks whether a given number is an armstrong number or not. Armstrong
* number is a number that is equal to the sum of cubes of its digits for
* example 0, 1, 153, 370, 371, 407 etc.
* Checks whether a given number is an armstrong number or not.
*
* @param number
* @return boolean
* @param number number to check
* @return {@code true} if given number is armstrong number, {@code false} otherwise
*/
public static boolean checkIfANumberIsAmstrongOrNot(int number) {
int remainder, sum = 0, temp = 0;
temp = number;
private static boolean isArmStrong(int number) {
int sum = 0;
int temp = number;
int numberOfDigits = 0;
while (temp != 0) {
numberOfDigits++;
temp /= 10;
}
temp = number; /* copy number again */
while (number > 0) {
remainder = number % 10;
sum = sum + (remainder * remainder * remainder);
number = number / 10;
int remainder = number % 10;
int power = 1;
for (int i = 1; i <= numberOfDigits; power *= remainder, ++i) ;
sum = sum + power;
number /= 10;
}
return sum == temp;
}
private static int inputInt(String string) {
System.out.print(string);
return Integer.parseInt(scan.nextLine());
}
}