To check if tree is valid BST tree or not (#180)

This commit is contained in:
Ayaan Faiz 2017-10-11 19:47:55 +05:30 committed by Chetan Kaushik
parent 7dacb2f837
commit 3244f5b698

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@ -0,0 +1,62 @@
class Node
{
int data;
Node left, right;
public Node(int item)
{
data = item;
left = right = null;
}
}
public class BinaryTree
{
//Root of the Binary Tree
Node root;
/* can give min and max value according to your code or
can write a function to find min and max value of tree. */
/* returns true if given search tree is binary
search tree (efficient version) */
boolean isBST() {
return isBSTUtil(root, Integer.MIN_VALUE,
Integer.MAX_VALUE);
}
/* Returns true if the given tree is a BST and its
values are >= min and <= max. */
boolean isBSTUtil(Node node, int min, int max)
{
/* an empty tree is BST */
if (node == null)
return true;
/* false if this node violates the min/max constraints */
if (node.data < min || node.data > max)
return false;
/* otherwise check the subtrees recursively
tightening the min/max constraints */
// Allow only distinct values
return (isBSTUtil(node.left, min, node.data-1) &&
isBSTUtil(node.right, node.data+1, max));
}
/* Driver program to test above functions */
public static void main(String args[])
{
BinaryTree tree = new BinaryTree();
tree.root = new Node(4);
tree.root.left = new Node(2);
tree.root.right = new Node(5);
tree.root.left.left = new Node(1);
tree.root.left.right = new Node(3);
if (tree.isBST())
System.out.println("IS BST");
else
System.out.println("Not a BST");
}
}