refactor: redesign LetterCombinationsOfPhoneNumber
(#5221)
* Refactor * fix clang * fix clang * fix clang tests * fix pattern * add test case null * Update src/main/java/com/thealgorithms/strings/LetterCombinationsOfPhoneNumber.java Co-authored-by: Piotr Idzik <65706193+vil02@users.noreply.github.com> * Update src/main/java/com/thealgorithms/strings/LetterCombinationsOfPhoneNumber.java Co-authored-by: Piotr Idzik <65706193+vil02@users.noreply.github.com> * Update src/main/java/com/thealgorithms/strings/LetterCombinationsOfPhoneNumber.java Co-authored-by: Piotr Idzik <65706193+vil02@users.noreply.github.com> * Update src/main/java/com/thealgorithms/strings/LetterCombinationsOfPhoneNumber.java Co-authored-by: Piotr Idzik <65706193+vil02@users.noreply.github.com> * Update src/main/java/com/thealgorithms/strings/LetterCombinationsOfPhoneNumber.java Co-authored-by: Piotr Idzik <65706193+vil02@users.noreply.github.com> * Update src/main/java/com/thealgorithms/strings/LetterCombinationsOfPhoneNumber.java Co-authored-by: Piotr Idzik <65706193+vil02@users.noreply.github.com> * Update src/test/java/com/thealgorithms/strings/LetterCombinationsOfPhoneNumberTest.java Co-authored-by: Piotr Idzik <65706193+vil02@users.noreply.github.com> * rename MAP_OF_CHARS to KEYPAD * fix clang * remove main * add tests * feat: throw for wrong inputs * change keypad to list * Update src/main/java/com/thealgorithms/strings/LetterCombinationsOfPhoneNumber.java Co-authored-by: Piotr Idzik <65706193+vil02@users.noreply.github.com> * Update src/main/java/com/thealgorithms/strings/LetterCombinationsOfPhoneNumber.java Co-authored-by: Piotr Idzik <65706193+vil02@users.noreply.github.com> * Update src/main/java/com/thealgorithms/strings/LetterCombinationsOfPhoneNumber.java Co-authored-by: Piotr Idzik <65706193+vil02@users.noreply.github.com> * fix with number 1 (empty value), and add tests * style: avoid concatenation while populating `KEYPAD` * change to assertEquals --------- Co-authored-by: Samuel Facchinello <samuel.facchinello@piksel.com> Co-authored-by: Piotr Idzik <65706193+vil02@users.noreply.github.com>
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@ -5,49 +5,61 @@ import java.util.Collections;
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import java.util.List;
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public final class LetterCombinationsOfPhoneNumber {
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private static final char EMPTY = '\0';
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// Mapping of numbers to corresponding letters on a phone keypad
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private static final String[] KEYPAD = new String[] {" ", String.valueOf(EMPTY), "abc", "def", "ghi", "jkl", "mno", "pqrs", "tuv", "wxyz"};
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private LetterCombinationsOfPhoneNumber() {
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}
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static Character[][] numberToCharMap;
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protected static List<String> printWords(int[] numbers, int len, int numIndex, String s) {
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if (len == numIndex) {
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return new ArrayList<>(Collections.singleton(s));
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/**
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* Generates a list of all possible letter combinations that the provided
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* array of numbers could represent on a phone keypad.
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*
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* @param numbers an array of integers representing the phone numbers
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* @return a list of possible letter combinations
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*/
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public static List<String> getCombinations(int[] numbers) {
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if (numbers == null) {
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return List.of("");
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}
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return generateCombinations(numbers, 0, new StringBuilder());
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}
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List<String> stringList = new ArrayList<>();
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for (int i = 0; i < numberToCharMap[numbers[numIndex]].length; i++) {
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String sCopy = String.copyValueOf(s.toCharArray());
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sCopy = sCopy.concat(numberToCharMap[numbers[numIndex]][i].toString());
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stringList.addAll(printWords(numbers, len, numIndex + 1, sCopy));
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}
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return stringList;
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/**
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* Recursive method to generate combinations of letters from the phone keypad.
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*
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* @param numbers the input array of phone numbers
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* @param index the current index in the numbers array being processed
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* @param current a StringBuilder holding the current combination of letters
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* @return a list of letter combinations formed from the given numbers
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*/
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private static List<String> generateCombinations(int[] numbers, int index, StringBuilder current) {
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// Base case: if we've processed all numbers, return the current combination
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if (index == numbers.length) {
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return new ArrayList<>(Collections.singletonList(current.toString()));
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}
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private static void printWords(int[] numbers) {
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generateNumberToCharMap();
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List<String> stringList = printWords(numbers, numbers.length, 0, "");
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stringList.stream().forEach(System.out::println);
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final var number = numbers[index];
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if (number < 0 || number > 9) {
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throw new IllegalArgumentException("Input numbers must in the range [0, 9]");
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}
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protected static void generateNumberToCharMap() {
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numberToCharMap = new Character[10][5];
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numberToCharMap[0] = new Character[] {'\0'};
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numberToCharMap[1] = new Character[] {'\0'};
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numberToCharMap[2] = new Character[] {'a', 'b', 'c'};
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numberToCharMap[3] = new Character[] {'d', 'e', 'f'};
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numberToCharMap[4] = new Character[] {'g', 'h', 'i'};
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numberToCharMap[5] = new Character[] {'j', 'k', 'l'};
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numberToCharMap[6] = new Character[] {'m', 'n', 'o'};
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numberToCharMap[7] = new Character[] {'p', 'q', 'r', 's'};
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numberToCharMap[8] = new Character[] {'t', 'u', 'v'};
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numberToCharMap[9] = new Character[] {'w', 'x', 'y', 'z'};
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List<String> combinations = new ArrayList<>();
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// Iterate over each letter and recurse to generate further combinations
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for (char letter : KEYPAD[number].toCharArray()) {
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if (letter != EMPTY) {
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current.append(letter);
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}
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combinations.addAll(generateCombinations(numbers, index + 1, current));
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if (letter != EMPTY) {
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current.deleteCharAt(current.length() - 1); // Backtrack by removing the last appended letter
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}
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}
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// Driver code
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public static void main(String[] args) {
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int[] number = {2, 3, 4};
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printWords(number);
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return combinations;
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}
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}
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@ -1,45 +1,37 @@
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package com.thealgorithms.strings;
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import static org.junit.jupiter.api.Assertions.assertTrue;
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import static org.junit.jupiter.api.Assertions.assertEquals;
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import static org.junit.jupiter.api.Assertions.assertThrows;
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import java.util.Arrays;
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import java.util.List;
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import org.junit.jupiter.api.Test;
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import java.util.stream.Stream;
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import org.junit.jupiter.params.ParameterizedTest;
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import org.junit.jupiter.params.provider.Arguments;
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import org.junit.jupiter.params.provider.MethodSource;
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public class LetterCombinationsOfPhoneNumberTest {
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@Test
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public void letterCombinationsOfPhoneNumber() {
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LetterCombinationsOfPhoneNumber.generateNumberToCharMap();
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@ParameterizedTest
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@MethodSource("provideTestCases")
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public void testLetterCombinationsOfPhoneNumber(int[] numbers, List<String> expectedOutput) {
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assertEquals(expectedOutput, LetterCombinationsOfPhoneNumber.getCombinations(numbers));
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}
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// ** Test 1 **
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// Input: digits = ""
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// Output: []
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int[] numbers1 = {};
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List<String> output1 = Arrays.asList("");
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assertTrue(LetterCombinationsOfPhoneNumber.printWords(numbers1, numbers1.length, 0, "").equals(output1));
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@ParameterizedTest
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@MethodSource("wrongInputs")
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void throwsForWrongInput(int[] numbers) {
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assertThrows(IllegalArgumentException.class, () -> LetterCombinationsOfPhoneNumber.getCombinations(numbers));
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}
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// ** Test 2 **
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// Input: digits = "2"
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// Output: ["a","b","c"]
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int[] numbers2 = {2};
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List<String> output2 = Arrays.asList("a", "b", "c");
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assertTrue(LetterCombinationsOfPhoneNumber.printWords(numbers2, numbers2.length, 0, "").equals(output2));
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private static Stream<Arguments> provideTestCases() {
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return Stream.of(Arguments.of(null, List.of("")), Arguments.of(new int[] {}, List.of("")), Arguments.of(new int[] {2}, List.of("a", "b", "c")), Arguments.of(new int[] {2, 3}, List.of("ad", "ae", "af", "bd", "be", "bf", "cd", "ce", "cf")),
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Arguments.of(new int[] {2, 3, 4}, List.of("adg", "adh", "adi", "aeg", "aeh", "aei", "afg", "afh", "afi", "bdg", "bdh", "bdi", "beg", "beh", "bei", "bfg", "bfh", "bfi", "cdg", "cdh", "cdi", "ceg", "ceh", "cei", "cfg", "cfh", "cfi")),
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Arguments.of(new int[] {3, 3}, List.of("dd", "de", "df", "ed", "ee", "ef", "fd", "fe", "ff")), Arguments.of(new int[] {8, 4}, List.of("tg", "th", "ti", "ug", "uh", "ui", "vg", "vh", "vi")), Arguments.of(new int[] {2, 0}, List.of("a ", "b ", "c ")),
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Arguments.of(new int[] {9, 2}, List.of("wa", "wb", "wc", "xa", "xb", "xc", "ya", "yb", "yc", "za", "zb", "zc")), Arguments.of(new int[] {0}, List.of(" ")), Arguments.of(new int[] {1}, List.of("")), Arguments.of(new int[] {2}, List.of("a", "b", "c")),
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Arguments.of(new int[] {1, 2, 0, 4}, List.of("a g", "a h", "a i", "b g", "b h", "b i", "c g", "c h", "c i")));
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}
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// ** Test 3 **
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// Input: digits = "23"
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// Output: ["ad","ae","af","bd","be","bf","cd","ce","cf"]
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int[] numbers3 = {2, 3};
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List<String> output3 = Arrays.asList("ad", "ae", "af", "bd", "be", "bf", "cd", "ce", "cf");
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assertTrue(LetterCombinationsOfPhoneNumber.printWords(numbers3, numbers3.length, 0, "").equals(output3));
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// ** Test 4 **
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// Input: digits = "234"
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// Output: ["adg", "adh", "adi", "aeg", "aeh", "aei", "afg", "afh", "afi",
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// "bdg", "bdh", "bdi", "beg", "beh", "bei", "bfg", "bfh", "bfi", "cdg", "cdh",
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// "cdi", "ceg", "ceh", "cei", "cfg", "cfh", "cfi"]
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int[] numbers4 = {2, 3, 4};
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List<String> output4 = Arrays.asList("adg", "adh", "adi", "aeg", "aeh", "aei", "afg", "afh", "afi", "bdg", "bdh", "bdi", "beg", "beh", "bei", "bfg", "bfh", "bfi", "cdg", "cdh", "cdi", "ceg", "ceh", "cei", "cfg", "cfh", "cfi");
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assertTrue(LetterCombinationsOfPhoneNumber.printWords(numbers4, numbers4.length, 0, "").equals(output4));
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private static Stream<Arguments> wrongInputs() {
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return Stream.of(Arguments.of(new int[] {-1}), Arguments.of(new int[] {10}), Arguments.of(new int[] {2, 2, -1, 0}), Arguments.of(new int[] {0, 0, 0, 10}));
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}
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}
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