refactor: PalindromicPartitioning (#5419)

refactor: PalindromicPartitioning

Co-authored-by: alxkm <alx@alx.com>
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Alex Klymenko 2024-08-28 20:53:00 +02:00 committed by GitHub
parent 0733075498
commit 7d1847f51c
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2 changed files with 40 additions and 26 deletions

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@ -1,27 +1,31 @@
package com.thealgorithms.dynamicprogramming; package com.thealgorithms.dynamicprogramming;
import java.util.Scanner;
/** /**
* @file @brief Implements [Palindrome * Provides functionality to solve the Palindrome Partitioning II problem, which involves finding
* Partitioning](https://leetcode.com/problems/palindrome-partitioning-ii/) * the minimum number of partitions needed to divide a given string into palindromic substrings.
* algorithm, giving you the minimum number of partitions you need to make
* *
* @details palindrome partitioning uses dynamic programming and goes to all the * <p>
* possible partitions to find the minimum you are given a string and you need * The problem is solved using dynamic programming. The approach involves checking all possible
* to give minimum number of partitions needed to divide it into a number of * substrings and determining whether they are palindromes. The minimum number of cuts required
* palindromes [Palindrome Partitioning] * for palindrome partitioning is computed in a bottom-up manner.
* (https://www.geeksforgeeks.org/palindrome-partitioning-dp-17/) overall time * </p>
* complexity O(n^2) For example: example 1:- String : "nitik" Output : 2 => "n *
* | iti | k" For example: example 2:- String : "ababbbabbababa" Output : 3 => * <p>
* "aba | b | bbabb | ababa" * Example:
* @author [Syed] (https://github.com/roeticvampire) * <ul>
* <li>Input: "nitik" => Output: 2 (Partitioning: "n | iti | k")</li>
* <li>Input: "ababbbabbababa" => Output: 3 (Partitioning: "aba | b | bbabb | ababa")</li>
* </ul>
* </p>
*
* @see <a href="https://leetcode.com/problems/palindrome-partitioning-ii/">Palindrome Partitioning II</a>
* @see <a href="https://www.geeksforgeeks.org/palindrome-partitioning-dp-17/">Palindrome Partitioning (GeeksforGeeks)</a>
*/ */
public final class PalindromicPartitioning { public final class PalindromicPartitioning {
private PalindromicPartitioning() { private PalindromicPartitioning() {
} }
public static int minimalpartitions(String word) { public static int minimalPartitions(String word) {
int len = word.length(); int len = word.length();
/* We Make two arrays to create a bottom-up solution. /* We Make two arrays to create a bottom-up solution.
minCuts[i] = Minimum number of cuts needed for palindrome partitioning of substring minCuts[i] = Minimum number of cuts needed for palindrome partitioning of substring
@ -76,15 +80,4 @@ public final class PalindromicPartitioning {
// string. i.e., str[0..n-1] // string. i.e., str[0..n-1]
return minCuts[len - 1]; return minCuts[len - 1];
} }
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String word;
System.out.println("Enter the First String");
word = input.nextLine();
// ans stores the final minimal cut count needed for partitioning
int ans = minimalpartitions(word);
System.out.println("The minimum cuts needed to partition \"" + word + "\" into palindromes is " + ans);
input.close();
}
} }

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package com.thealgorithms.dynamicprogramming;
import static org.junit.jupiter.api.Assertions.assertEquals;
import java.util.stream.Stream;
import org.junit.jupiter.params.ParameterizedTest;
import org.junit.jupiter.params.provider.Arguments;
import org.junit.jupiter.params.provider.MethodSource;
public class PalindromicPartitioningTest {
private static Stream<Arguments> provideTestCases() {
return Stream.of(Arguments.of("a", 0), Arguments.of("aa", 0), Arguments.of("ab", 1), Arguments.of("ababbbabbababa", 3), Arguments.of("abcde", 4), Arguments.of("abacdcaba", 0));
}
@ParameterizedTest
@MethodSource("provideTestCases")
public void testMinimalPartitions(String input, int expected) {
assertEquals(expected, PalindromicPartitioning.minimalPartitions(input));
}
}