Merge pull request #195 from ayaanfaiz/master
Added Trees Basic Programs.
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import java.util.Queue;
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import java.util.LinkedList;
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/* Class to represent Tree node */
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class Node {
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int data;
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Node left, right;
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public Node(int item) {
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data = item;
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left = null;
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right = null;
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}
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}
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/* Class to print Level Order Traversal */
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class BinaryTree {
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Node root;
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/* Given a binary tree. Print its nodes in level order
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using array for implementing queue */
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void printLevelOrder()
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{
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Queue<Node> queue = new LinkedList<Node>();
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queue.add(root);
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while (!queue.isEmpty())
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{
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/* poll() removes the present head.
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For more information on poll() visit
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http://www.tutorialspoint.com/java/util/linkedlist_poll.htm */
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Node tempNode = queue.poll();
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System.out.print(tempNode.data + " ");
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/*Enqueue left child */
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if (tempNode.left != null) {
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queue.add(tempNode.left);
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}
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/*Enqueue right child */
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if (tempNode.right != null) {
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queue.add(tempNode.right);
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}
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}
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}
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public static void main(String args[])
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{
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/* creating a binary tree and entering
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the nodes */
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BinaryTree tree_level = new BinaryTree();
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tree_level.root = new Node(1);
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tree_level.root.left = new Node(2);
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tree_level.root.right = new Node(3);
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tree_level.root.left.left = new Node(4);
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tree_level.root.left.right = new Node(5);
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System.out.println("Level order traversal of binary tree is - ");
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tree_level.printLevelOrder();
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}
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}
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78
data_structures/Trees/Level Order Traversal.java
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78
data_structures/Trees/Level Order Traversal.java
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class Node
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{
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int data;
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Node left, right;
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public Node(int item)
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{
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data = item;
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left = right = null;
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}
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}
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class BinaryTree
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{
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// Root of the Binary Tree
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Node root;
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public BinaryTree()
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{
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root = null;
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}
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/* function to print level order traversal of tree*/
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void printLevelOrder()
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{
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int h = height(root);
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int i;
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for (i=1; i<=h; i++)
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printGivenLevel(root, i);
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}
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/* Compute the "height" of a tree -- the number of
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nodes along the longest path from the root node
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down to the farthest leaf node.*/
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int height(Node root)
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{
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if (root == null)
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return 0;
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else
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{
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/* compute height of each subtree */
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int lheight = height(root.left);
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int rheight = height(root.right);
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/* use the larger one */
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if (lheight > rheight)
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return(lheight+1);
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else return(rheight+1);
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}
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}
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/* Print nodes at the given level */
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void printGivenLevel (Node root ,int level)
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{
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if (root == null)
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return;
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if (level == 1)
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System.out.print(root.data + " ");
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else if (level > 1)
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{
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printGivenLevel(root.left, level-1);
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printGivenLevel(root.right, level-1);
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}
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}
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/* Driver program to test above functions */
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public static void main(String args[])
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{
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BinaryTree tree = new BinaryTree();
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tree.root= new Node(1);
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tree.root.left= new Node(2);
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tree.root.right= new Node(3);
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tree.root.left.left= new Node(4);
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tree.root.left.right= new Node(5);
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System.out.println("Level order traversal of binary tree is ");
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tree.printLevelOrder();
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}
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}
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105
data_structures/Trees/Print Top View of Tree.java
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105
data_structures/Trees/Print Top View of Tree.java
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// Java program to print top view of Binary tree
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import java.util.*;
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// Class for a tree node
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class TreeNode
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{
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// Members
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int key;
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TreeNode left, right;
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// Constructor
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public TreeNode(int key)
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{
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this.key = key;
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left = right = null;
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}
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}
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// A class to represent a queue item. The queue is used to do Level
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// order traversal. Every Queue item contains node and horizontal
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// distance of node from root
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class QItem
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{
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TreeNode node;
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int hd;
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public QItem(TreeNode n, int h)
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{
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node = n;
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hd = h;
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}
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}
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// Class for a Binary Tree
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class Tree
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{
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TreeNode root;
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// Constructors
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public Tree() { root = null; }
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public Tree(TreeNode n) { root = n; }
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// This method prints nodes in top view of binary tree
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public void printTopView()
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{
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// base case
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if (root == null) { return; }
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// Creates an empty hashset
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HashSet<Integer> set = new HashSet<>();
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// Create a queue and add root to it
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Queue<QItem> Q = new LinkedList<QItem>();
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Q.add(new QItem(root, 0)); // Horizontal distance of root is 0
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// Standard BFS or level order traversal loop
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while (!Q.isEmpty())
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{
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// Remove the front item and get its details
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QItem qi = Q.remove();
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int hd = qi.hd;
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TreeNode n = qi.node;
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// If this is the first node at its horizontal distance,
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// then this node is in top view
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if (!set.contains(hd))
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{
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set.add(hd);
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System.out.print(n.key + " ");
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}
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// Enqueue left and right children of current node
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if (n.left != null)
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Q.add(new QItem(n.left, hd-1));
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if (n.right != null)
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Q.add(new QItem(n.right, hd+1));
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}
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}
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}
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// Driver class to test above methods
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public class Main
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{
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public static void main(String[] args)
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{
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/* Create following Binary Tree
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1
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/ \
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2 3
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\
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4
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\
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5
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\
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6*/
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TreeNode root = new TreeNode(1);
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root.left = new TreeNode(2);
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root.right = new TreeNode(3);
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root.left.right = new TreeNode(4);
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root.left.right.right = new TreeNode(5);
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root.left.right.right.right = new TreeNode(6);
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Tree t = new Tree(root);
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System.out.println("Following are nodes in top view of Binary Tree");
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t.printTopView();
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}
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}
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