JavaAlgorithms/DynamicProgramming/MinimumSumPartition.java
Hrishikesh Padhye 6f8f5bebfe
Update and rename Minimum sum partition to MinimumSumPartition.java
Updated the file name and indentations to increase the readability
2020-08-02 11:06:09 +05:30

74 lines
1.6 KiB
Java

// Partition a set into two subsets such that the difference of subset sums is minimum
/*
Input: arr[] = {1, 6, 11, 5}
Output: 1
Explanation:
Subset1 = {1, 5, 6}, sum of Subset1 = 12
Subset2 = {11}, sum of Subset2 = 11
Input: arr[] = {36, 7, 46, 40}
Output: 23
Explanation:
Subset1 = {7, 46} ; sum of Subset1 = 53
Subset2 = {36, 40} ; sum of Subset2 = 76
*/
import java.util.*;
import java.lang.*;
import java.io.*;
class GFG
{
public static void main (String[] args)
{
Scanner sc=new Scanner(System.in);
int t=sc.nextInt();
while(t-->0)
{
int n=sc.nextInt();
int arr[]=new int[n];
int sum=0;
for(int i=0;i<n;i++)
{
arr[i]=sc.nextInt();
sum+=arr[i];
}
int ans[]=new int[sum];
ans=subset(arr,sum);
int min=Integer.MAX_VALUE;
for(int i=0;i<ans.length;i++)
min=Math.min(min,(sum-2*ans[i]));
System.out.println(min);
}
}
static int[] subset(int arr[],int sum)
{
int n=arr.length;
boolean dp[][]=new boolean[n+1][sum+1];
for(int i=0;i<=n;i++)
dp[i][0]=true;
for(int i=1;i<=sum;i++)
dp[0][i]=false;
// subset sum concept
for(int i=1;i<=n;i++)
{
for(int j=1;j<=sum;j++)
{
if(arr[i-1]<=j)
dp[i][j]=dp[i-1][j-arr[i-1]] || dp[i-1][j];
else
dp[i][j]=dp[i-1][j];
}
}
//storing last dp column whose value is true till sum/2
int index[]=new int[sum];
int p=0;
for(int i=0;i<=sum/2;i++)
{
if(dp[n][i]==true)
index[p++]=i;
}
return index;
}
}