JavaAlgorithms/DynamicProgramming/BoardPath.java
2020-08-02 07:59:49 -05:00

78 lines
1.6 KiB
Java

package DynamicProgramming;
/*
* this is an important Algo in which
* we have starting and ending of board and we have to reach
* we have to count no. of ways
* that help to reach end point i.e number by rolling dice
* which have 1 to 6 digits
Test Case:
here target is 10
int n=10;
startAlgo();
System.out.println(bpR(0,n));
System.out.println(endAlgo()+"ms");
int[] strg=new int [n+1];
startAlgo();
System.out.println(bpRS(0,n,strg));
System.out.println(endAlgo()+"ms");
startAlgo();
System.out.println(bpIS(0,n,strg));
System.out.println(endAlgo()+"ms");
*/
public class BoardPath {
public static long startTime;
public static long endTime;
public static void startAlgo() {
startTime=System.currentTimeMillis();
}
public static long endAlgo() {
endTime=System.currentTimeMillis();
return endTime-startTime;
}
public static int bpR(int start,int end){
if(start==end) {
return 1;
}
else if(start>end)
return 0;
int count=0;
for(int dice=1;dice<=6;dice++) {
count+=bpR(start+dice,end);
}
return count;
}
public static int bpRS(int curr,int end,int strg[]){
if(curr==end) {
return 1;
}
else if(curr>end)
return 0;
if(strg[curr]!=0)
return strg[curr];
int count=0;
for(int dice=1;dice<=6;dice++) {
count+=bpRS(curr+dice,end,strg);
}
strg[curr]=count;
return count;
}
public static int bpIS(int curr,int end,int[]strg){
strg[end]=1;
for(int i=end-1;i>=0;i--) {
int count=0;
for(int dice=1;dice<=6&&dice+i<strg.length;dice++) {
count+=strg[i+dice];
}
strg[i]=count;
}
return strg[0];
}
}