34 lines
945 B
Java
34 lines
945 B
Java
import java.io.*;
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import java.util.*;
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import java.text.*;
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import java.math.*;
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import java.util.regex.*;
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public class Solution {
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public static void main(String[] args) {
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//take input
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Scanner scn = new Scanner(System.in);
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int N = scn.nextInt(); //N is the input number
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int P = scn.nextInt(); //P is precision value for eg - P is 3 in 2.564 and 5 in 3.80870.
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System.out.println(squareRoot(N, P));
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}
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public static double squareRoot(int N, int P) {
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double rv = 0; //rv means return value
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double root = Math.pow(N, 0.5);
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//calculate precision to power of 10 and then multiply it with root value.
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int precision = (int) Math.pow(10, P);
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root = root * precision;
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/*typecast it into integer then divide by precision and again typecast into double
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so as to have decimal points upto P precision */
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rv = (int)root;
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return (double)rv/precision;
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}
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}
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