{ "cells": [ { "cell_type": "code", "execution_count": 55, "metadata": {}, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "Original Topics:\n", "['tech', 'business', 'sport', 'entertainment', 'politics']\n", "1/10\n", "2/10\n", "3/10\n", "4/10\n", "5/10\n", "6/10\n", "7/10\n", "8/10\n", "9/10\n", "10/10\n", "Topic 1: said year government people mobile last number growth phone market\n", "Topic 2: said people film could would also technology made make government\n", "Topic 3: said would could best music also world election labour people\n", "Topic 4: said first england also time game players wales would team\n", "Topic 5: said also would company year world sales firm market last\n", "Time: 531.1292963027954\n" ] } ], "source": [ "import numpy as np\n", "import pandas as pd\n", "import string\n", "from nltk.corpus import stopwords\n", "import time\n", "\n", "\n", "#定义加载数据的函数\n", "def load_data(file):\n", " '''\n", " INPUT:\n", " file - (str) 数据文件的路径\n", " \n", " OUTPUT:\n", " org_topics - (list) 原始话题标签列表\n", " text - (list) 文本列表\n", " words - (list) 单词列表\n", " \n", " '''\n", " df = pd.read_csv(file) #读取文件\n", " org_topics = df['category'].unique().tolist() #保存文本原始的话题标签\n", " df.drop('category', axis=1, inplace=True)\n", " n = df.shape[0] #n为文本数量\n", " text = []\n", " words = []\n", " for i in df['text'].values:\n", " t = i.translate(str.maketrans('', '', string.punctuation)) #去除文本中的标点符号\n", " t = [j for j in t.split() if j not in stopwords.words('english')] #去除文本中的停止词\n", " t = [j for j in t if len(j) > 3] #长度小于等于3的单词大多是无意义的,直接去除\n", " text.append(t) #将处理后的文本保存到文本列表中\n", " words.extend(set(t)) #将文本中所包含的单词保存到单词列表中\n", " words = list(set(words)) #去除单词列表中的重复单词\n", " return org_topics, text, words\n", "\n", "\n", "#定义构建单词-文本矩阵的函数,这里矩阵的每一项表示单词在文本中的出现频次,也可以用TF-IDF来表示\n", "def frequency_counter(text, words):\n", " '''\n", " INPUT:\n", " text - (list) 文本列表\n", " words - (list) 单词列表\n", " \n", " OUTPUT:\n", " words - (list) 出现频次为前1000的单词列表\n", " X - (array) 单词-文本矩阵\n", " \n", " '''\n", " words_cnt = np.zeros(len(words)) #用来保存单词的出现频次\n", " X = np.zeros((1000, len(text))) #定义m*n的矩阵,其中m为单词列表中的单词个数,为避免运行时间过长,这里只取了出现频次为前1000的单词,因此m为1000,n为文本个数\n", " #循环计算words列表中各单词出现的词频\n", " for i in range(len(text)):\n", " t = text[i] #取出第i条文本\n", " for w in t:\n", " ind = words.index(w) #取出第i条文本中的第t个单词在单词列表中的索引\n", " words_cnt[ind] += 1 #对应位置的单词出现频次加一\n", " sort_inds = np.argsort(words_cnt)[::-1] #对单词出现频次降序排列后取出其索引值\n", " words = [words[ind] for ind in sort_inds[:1000]] #将出现频次前1000的单词保存到words列表\n", " #构建单词-文本矩阵\n", " for i in range(len(text)):\n", " t = text[i] #取出第i条文本\n", " for w in t:\n", " if w in words: #如果文本t中的单词w在单词列表中,则将X矩阵中对应位置加一\n", " ind = words.index(w)\n", " X[ind, i] += 1\n", " return words, X\n", "\n", "\n", "#定义概率潜在语义分析函数,采用EM算法进行PLSA模型的参数估计\n", "def do_plsa(X, K, words, iters = 10):\n", " '''\n", " INPUT:\n", " X - (array) 单词-文本矩阵\n", " K - (int) 设定的话题数\n", " words - (list) 出现频次为前1000的单词列表\n", " iters - (int) 设定的迭代次数\n", " \n", " OUTPUT:\n", " P_wi_zk - (array) 话题zk条件下产生单词wi的概率数组\n", " P_zk_dj - (array) 文本dj条件下属于话题zk的概率数组\n", " \n", " '''\n", " M, N = X.shape #M为单词数,N为文本数\n", " #P_wi_zk表示P(wi|zk),是一个K*M的数组,其中每个值表示第k个话题zk条件下产生第i个单词wi的概率,这里将每个值随机初始化为0-1之间的浮点数\n", " P_wi_zk = np.random.rand(K, M)\n", " #对于每个话题zk,保证产生单词wi的概率的总和为1\n", " for k in range(K):\n", " P_wi_zk[k] /= np.sum(P_wi_zk[k])\n", " #P_zk_dj表示P(zk|dj),是一个N*K的数组,其中每个值表示第j个文本dj条件下产生第k个话题zk的概率,这里将每个值随机初始化为0-1之间的浮点数\n", " P_zk_dj = np.random.rand(N, K)\n", " #对于每个文本dj,属于话题zk的概率的总和为1\n", " for n in range(N):\n", " P_zk_dj[n] /= np.sum(P_zk_dj[n])\n", " #P_zk_wi_dj表示P(zk|wi,dj),是一个M*N*K的数组,其中每个值表示在单词-文本对(wi,dj)的条件下属于第k个话题zk的概率,这里设置初始值为0\n", " P_zk_wi_dj = np.zeros((M, N, K))\n", " #迭代执行E步和M步\n", " for i in range(iters):\n", " print('{}/{}'.format(i+1, iters)) \n", " #执行E步\n", " for m in range(M):\n", " for n in range(N):\n", " sums = 0\n", " for k in range(K):\n", " P_zk_wi_dj[m, n, k] = P_wi_zk[k, m] * P_zk_dj[n, k] #计算P(zk|wi,dj)的分子部分,即P(wi|zk)*P(zk|dj)\n", " sums += P_zk_wi_dj[m, n, k] #计算P(zk|wi,dj)的分母部分,即P(wi|zk)*P(zk|dj)在K个话题上的总和\n", " P_zk_wi_dj[m, n, :] = P_zk_wi_dj[m, n, :] / sums #得到单词-文本对(wi,dj)条件下的P(zk|wi,dj)\n", " #执行M步,计算P(wi|zk)\n", " for k in range(K):\n", " s1 = 0\n", " for m in range(M):\n", " P_wi_zk[k, m] = 0\n", " for n in range(N):\n", " P_wi_zk[k, m] += X[m, n] * P_zk_wi_dj[m, n, k] #计算P(wi|zk)的分子部分,即n(wi,dj)*P(zk|wi,dj)在N个文本上的总和,其中n(wi,dj)为单词-文本矩阵X在文本对(wi,dj)处的频次\n", " s1 += P_wi_zk[k, m] #计算P(wi|zk)的分母部分,即n(wi,dj)*P(zk|wi,dj)在N个文本和M个单词上的总和\n", " P_wi_zk[k, :] = P_wi_zk[k, :] / s1 #得到话题zk条件下的P(wi|zk)\n", " #执行M步,计算P(zk|dj)\n", " for n in range(N):\n", " for k in range(K):\n", " P_zk_dj[n, k] = 0\n", " for m in range(M):\n", " P_zk_dj[n, k] += X[m, n] * P_zk_wi_dj[m, n, k] #同理计算P(zk|dj)的分子部分,即n(wi,dj)*P(zk|wi,dj)在N个文本上的总和\n", " P_zk_dj[n, k] = P_zk_dj[n, k] / np.sum(X[:, n]) #得到文本dj条件下的P(zk|dj),其中n(dj)为文本dj中的单词个数,由于我们只取了出现频次前1000的单词,所以这里n(dj)计算的是文本dj中在单词列表中的单词数\n", " return P_wi_zk, P_zk_dj\n", "\n", "\n", "if __name__ == \"__main__\":\n", " org_topics, text, words = load_data('bbc_text.csv') #加载数据\n", " print('Original Topics:')\n", " print(org_topics) #打印原始的话题标签列表\n", " start = time.time() #保存开始时间\n", " words, X = frequency_counter(text, words) #取频次前1000的单词重新构建单词列表,并构建单词-文本矩阵\n", " K = 5 #设定话题数为5\n", " P_wi_zk, P_zk_dj = do_plsa(X, K, words, iters = 10) #采用EM算法对PLSA模型进行参数估计\n", " #打印出每个话题zk条件下出现概率最大的前10个单词,即P(wi|zk)在话题zk中最大的10个值对应的单词,作为对话题zk的文本描述\n", " for k in range(K):\n", " sort_inds = np.argsort(P_wi_zk[k])[::-1] #对话题zk条件下的P(wi|zk)的值进行降序排列后取出对应的索引值\n", " topic = [] #定义一个空列表用于保存话题zk概率最大的前10个单词\n", " for i in range(10):\n", " topic.append(words[sort_inds[i]]) \n", " topic = ' '.join(topic) #将10个单词以空格分隔,构成对话题zk的文本表述\n", " print('Topic {}: {}'.format(k+1, topic)) #打印话题zk\n", " end = time.time()\n", " print('Time:', end-start)" ] }, { "cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": [] } ], "metadata": { "kernelspec": { "display_name": "Python 3", "language": "python", "name": "python3" }, "language_info": { "codemirror_mode": { "name": "ipython", "version": 3 }, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython3", "version": "3.7.3" } }, "nbformat": 4, "nbformat_minor": 2 }