341 lines
8.0 KiB
Java
341 lines
8.0 KiB
Java
package linkedlist;
|
||
|
||
/**
|
||
* 1)单链表的插入、删除、查找操作;
|
||
* 2)链表中存储的是int类型的数据;
|
||
*
|
||
* Author:Zheng
|
||
*/
|
||
public class SinglyLinkedList {
|
||
|
||
private Node head = null;
|
||
|
||
public Node findByValue(int value) {
|
||
Node p = head;
|
||
while (p != null && p.data != value) {
|
||
p = p.next;
|
||
}
|
||
|
||
return p;
|
||
}
|
||
|
||
public Node findByIndex(int index) {
|
||
Node p = head;
|
||
int pos = 0;
|
||
while (p != null && pos != index) {
|
||
p = p.next;
|
||
++pos;
|
||
}
|
||
|
||
return p;
|
||
}
|
||
|
||
//无头结点
|
||
//表头部插入
|
||
//这种操作将于输入的顺序相反,逆序
|
||
public void insertToHead(int value) {
|
||
Node newNode = new Node(value, null);
|
||
insertToHead(newNode);
|
||
}
|
||
|
||
public void insertToHead(Node newNode) {
|
||
if (head == null) {
|
||
head = newNode;
|
||
} else {
|
||
newNode.next = head;
|
||
head = newNode;
|
||
}
|
||
}
|
||
|
||
//顺序插入
|
||
//链表尾部插入
|
||
public void insertTail(int value){
|
||
|
||
Node newNode = new Node(value, null);
|
||
//空链表,可以插入新节点作为head,也可以不操作
|
||
if (head == null){
|
||
head = newNode;
|
||
|
||
}else{
|
||
Node q = head;
|
||
while(q.next != null){
|
||
q = q.next;
|
||
}
|
||
newNode.next = q.next;
|
||
q.next = newNode;
|
||
}
|
||
}
|
||
public void insertAfter(Node p, int value) {
|
||
Node newNode = new Node(value, null);
|
||
insertAfter(p, newNode);
|
||
}
|
||
|
||
public void insertAfter(Node p, Node newNode) {
|
||
if (p == null) return;
|
||
|
||
newNode.next = p.next;
|
||
p.next = newNode;
|
||
}
|
||
|
||
public void insertBefore(Node p, int value) {
|
||
Node newNode = new Node(value, null);
|
||
insertBefore(p, newNode);
|
||
}
|
||
|
||
public void insertBefore(Node p, Node newNode) {
|
||
if (p == null) return;
|
||
if (head == p) {
|
||
insertToHead(newNode);
|
||
return;
|
||
}
|
||
|
||
Node q = head;
|
||
while (q != null && q.next != p) {
|
||
q = q.next;
|
||
}
|
||
|
||
if (q == null) {
|
||
return;
|
||
}
|
||
|
||
newNode.next = p;
|
||
q.next = newNode;
|
||
|
||
}
|
||
|
||
public void deleteByNode(Node p) {
|
||
if (p == null || head == null) return;
|
||
|
||
if (p == head) {
|
||
head = head.next;
|
||
return;
|
||
}
|
||
|
||
Node q = head;
|
||
while (q != null && q.next != p) {
|
||
q = q.next;
|
||
}
|
||
|
||
if (q == null) {
|
||
return;
|
||
}
|
||
|
||
q.next = q.next.next;
|
||
}
|
||
|
||
public void deleteByValue(int value) {
|
||
if (head == null) return;
|
||
|
||
Node p = head;
|
||
Node q = null;
|
||
while (p != null && p.data != value) {
|
||
q = p;
|
||
p = p.next;
|
||
}
|
||
|
||
if (p == null) return;
|
||
|
||
if (q == null) {
|
||
head = head.next;
|
||
} else {
|
||
q.next = q.next.next;
|
||
}
|
||
|
||
// 可重复删除指定value的代码
|
||
/*
|
||
if (head != null && head.data == value) {
|
||
head = head.next;
|
||
}
|
||
|
||
Node pNode = head;
|
||
while (pNode != null) {
|
||
if (pNode.next.data == data) {
|
||
pNode.next = pNode.next.next;
|
||
continue;
|
||
}
|
||
pNode = pNode.next;
|
||
}
|
||
*/
|
||
}
|
||
|
||
public void printAll() {
|
||
Node p = head;
|
||
while (p != null) {
|
||
System.out.print(p.data + " ");
|
||
p = p.next;
|
||
}
|
||
System.out.println();
|
||
}
|
||
|
||
//判断true or false
|
||
public boolean TFResult(Node left, Node right){
|
||
Node l = left;
|
||
Node r = right;
|
||
|
||
boolean flag=true;
|
||
System.out.println("left_:"+l.data);
|
||
System.out.println("right_:"+r.data);
|
||
while(l != null && r != null){
|
||
if (l.data == r.data){
|
||
l = l.next;
|
||
r = r.next;
|
||
continue;
|
||
}else{
|
||
flag=false;
|
||
break;
|
||
}
|
||
|
||
}
|
||
|
||
System.out.println("什么结果");
|
||
return flag;
|
||
/* if (l==null && r==null){
|
||
System.out.println("什么结果");
|
||
return true;
|
||
}else{
|
||
return false;
|
||
}*/
|
||
}
|
||
// 判断是否为回文
|
||
|
||
public boolean palindrome(){
|
||
if (head == null){
|
||
return false;
|
||
}else{
|
||
System.out.println("开始执行找到中间节点");
|
||
Node p = head;
|
||
Node q = head;
|
||
if (p.next == null){
|
||
System.out.println("只有一个元素");
|
||
return true;
|
||
}
|
||
while( q.next != null && q.next.next != null){
|
||
p = p.next;
|
||
q = q.next.next;
|
||
|
||
}
|
||
|
||
System.out.println("中间节点" + p.data);
|
||
System.out.println("开始执行奇数节点的回文判断");
|
||
Node leftLink = null;
|
||
Node rightLink = null;
|
||
if(q.next == null){
|
||
// p 一定为整个链表的中点,且节点数目为奇数
|
||
rightLink = p.next;
|
||
leftLink = inverseLinkList(p).next;
|
||
System.out.println("左边第一个节点"+leftLink.data);
|
||
System.out.println("右边第一个节点"+rightLink.data);
|
||
|
||
}else{
|
||
//p q 均为中点
|
||
rightLink = p.next;
|
||
leftLink = inverseLinkList(p);
|
||
}
|
||
return TFResult(leftLink, rightLink);
|
||
|
||
}
|
||
}
|
||
|
||
//带结点的链表翻转
|
||
public Node inverseLinkList_head(Node p){
|
||
// Head 为新建的一个头结点
|
||
Node Head = new Node(9999,null);
|
||
// p 为原来整个链表的头结点,现在Head指向 整个链表
|
||
Head.next = p;
|
||
/*
|
||
带头结点的链表翻转等价于
|
||
从第二个元素开始重新头插法建立链表
|
||
*/
|
||
Node Cur = p.next;
|
||
p.next = null;
|
||
Node next = null;
|
||
|
||
while(Cur != null){
|
||
next = Cur.next;
|
||
Cur.next = Head.next;
|
||
Head.next = Cur;
|
||
System.out.println("first " + Head.data);
|
||
|
||
Cur = next;
|
||
}
|
||
|
||
// 返回左半部分的中点之前的那个节点
|
||
// 从此处开始同步像两边比较
|
||
return Head;
|
||
|
||
}
|
||
|
||
//无头结点的链表翻转
|
||
public Node inverseLinkList(Node p){
|
||
|
||
Node pre = null;
|
||
Node r = head;
|
||
System.out.println("z---" + r.data);
|
||
Node next= null;
|
||
while(r !=p){
|
||
next = r.next;
|
||
|
||
r.next = pre;
|
||
pre = r;
|
||
r = next;
|
||
}
|
||
|
||
r.next = pre;
|
||
// 返回左半部分的中点之前的那个节点
|
||
// 从此处开始同步像两边比较
|
||
return r;
|
||
|
||
}
|
||
|
||
public static Node createNode(int value) {
|
||
return new Node(value, null);
|
||
}
|
||
|
||
public static class Node {
|
||
private int data;
|
||
private Node next;
|
||
|
||
public Node(int data, Node next) {
|
||
this.data = data;
|
||
this.next = next;
|
||
}
|
||
|
||
public int getData() {
|
||
return data;
|
||
}
|
||
}
|
||
|
||
public static void main(String[]args){
|
||
|
||
SinglyLinkedList link = new SinglyLinkedList();
|
||
System.out.println("hello");
|
||
//int data[] = {1};
|
||
//int data[] = {1,2};
|
||
//int data[] = {1,2,3,1};
|
||
//int data[] = {1,2,5};
|
||
//int data[] = {1,2,2,1};
|
||
// int data[] = {1,2,5,2,1};
|
||
int data[] = {1,2,5,3,1};
|
||
|
||
for(int i =0; i < data.length; i++){
|
||
//link.insertToHead(data[i]);
|
||
link.insertTail(data[i]);
|
||
}
|
||
// link.printAll();
|
||
// Node p = link.inverseLinkList_head(link.head);
|
||
// while(p != null){
|
||
// System.out.println("aa"+p.data);
|
||
// p = p.next;
|
||
// }
|
||
|
||
System.out.println("打印原始:");
|
||
link.printAll();
|
||
if (link.palindrome()){
|
||
System.out.println("回文");
|
||
}else{
|
||
System.out.println("不是回文");
|
||
}
|
||
}
|
||
|
||
}
|