add NumberOfDigits

This commit is contained in:
shellhub 2020-08-12 22:51:19 +08:00
parent 2bd49e4728
commit 22e2e74bf8

62
Maths/NumberOfDigits.java Normal file
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@ -0,0 +1,62 @@
package Maths;
/**
* Find the number of digits in a number.
*/
public class NumberOfDigits {
public static void main(String[] args) {
int[] numbers = {0, 12, 123, 1234, -12345, 123456, 1234567, 12345678, 123456789};
for (int i = 0; i < numbers.length; ++i) {
assert numberOfDigits(numbers[i]) == i + 1;
assert numberOfDigitsFast(numbers[i]) == i + 1;
assert numberOfDigitsFaster(numbers[i]) == i + 1;
assert numberOfDigitsRecursion(numbers[i]) == i + 1;
}
}
/**
* Find the number of digits in a number.
*
* @param number number to find
* @return number of digits of given number
*/
private static int numberOfDigits(int number) {
int digits = 0;
do {
digits++;
number /= 10;
} while (number != 0);
return digits;
}
/**
* Find the number of digits in a number fast version.
*
* @param number number to find
* @return number of digits of given number
*/
private static int numberOfDigitsFast(int number) {
return number == 0 ? 1 : (int) Math.floor(Math.log10(Math.abs(number)) + 1);
}
/**
* Find the number of digits in a number faster version.
*
* @param number number to find
* @return number of digits of given number
*/
private static int numberOfDigitsFaster(int number) {
return number < 0 ? (-number + "").length() : (number + "").length();
}
/**
* Find the number of digits in a number using recursion.
*
* @param number number to find
* @return number of digits of given number
*/
private static int numberOfDigitsRecursion(int number) {
return number / 10 == 0 ? 1 : 1 + numberOfDigitsRecursion(number / 10);
}
}