Fix: 2618: [Enhancement] Combinations (#2625)

Co-authored-by: Amit Kumar <akumar@indeed.com>
This commit is contained in:
Amit Kumar 2021-10-20 13:52:32 +05:30 committed by GitHub
parent 4a2b190160
commit 3028cf58d8
No known key found for this signature in database
GPG Key ID: 4AEE18F83AFDEB23

View File

@ -7,6 +7,17 @@ public class Combinations {
assert combinations(10, 5) == 252;
assert combinations(6, 3) == 20;
assert combinations(20, 5) == 15504;
// Since, 200 is a big number its factorial will go beyond limits of long even when 200C5 can be saved in a long
// variable. So below will fail
// assert combinations(200, 5) == 2535650040l;
assert combinationsOptimized(100, 0) == 1;
assert combinationsOptimized(1, 1) == 1;
assert combinationsOptimized(10, 5) == 252;
assert combinationsOptimized(6, 3) == 20;
assert combinationsOptimized(20, 5) == 15504;
assert combinationsOptimized(200, 5) == 2535650040l;
}
/**
@ -32,4 +43,32 @@ public class Combinations {
public static long combinations(int n, int k) {
return factorial(n) / (factorial(k) * factorial(n - k));
}
/**
* The above method can exceed limit of long (overflow) when factorial(n) is larger than limits of long variable.
* Thus even if nCk is within range of long variable above reason can lead to incorrect result.
* This is an optimized version of computing combinations.
* Observations:
* nC(k + 1) = (n - k) * nCk / (k + 1)
* We know the value of nCk when k = 1 which is nCk = n
* Using this base value and above formula we can compute the next term nC(k+1)
* @param n
* @param k
* @return nCk
*/
public static long combinationsOptimized(int n, int k) {
if (n < 0 || k < 0) {
throw new IllegalArgumentException("n or k can't be negative");
}
if (n < k) {
throw new IllegalArgumentException("n can't be smaller than k");
}
// nC0 is always 1
long solution = 1;
for(int i = 0; i < k; i++) {
long next = (n - i) * solution / (i + 1);
solution = next;
}
return solution;
}
}