Add Partition Problem (#4182)
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/**
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* @author Md Asif Joardar
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*
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* Description: The partition problem is a classic problem in computer science
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* that asks whether a given set can be partitioned into two subsets such that
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* the sum of elements in each subset is the same.
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*
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* Example:
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* Consider nums = {1, 2, 3}
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* We can split the array "nums" into two partitions, where each having a sum of 3.
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* nums1 = {1, 2}
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* nums2 = {3}
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*
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* The time complexity of the solution is O(n × sum) and requires O(n × sum) space
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*/
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package com.thealgorithms.dynamicprogramming;
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import java.util.Arrays;
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public class PartitionProblem {
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/**
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* Test if a set of integers can be partitioned into two subsets such that the sum of elements
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* in each subset is the same.
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*
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* @param nums the array contains integers.
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* @return {@code true} if two subset exists, otherwise {@code false}.
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*/
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public static boolean partition(int[] nums)
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{
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// calculate the sum of all the elements in the array
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int sum = Arrays.stream(nums).sum();
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// it will return true if the sum is even and the array can be divided into two subarrays/subset with equal sum.
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// and here i reuse the SubsetSum class from dynamic programming section to check if there is exists a
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// subsetsum into nums[] array same as the given sum
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return (sum & 1) == 0 && SubsetSum.subsetSum(nums, sum/2);
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}
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}
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@ -22,7 +22,7 @@ public class SubsetSum {
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* @param sum target sum of subset.
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* @return {@code true} if subset exists, otherwise {@code false}.
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*/
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private static boolean subsetSum(int[] arr, int sum) {
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public static boolean subsetSum(int[] arr, int sum) {
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int n = arr.length;
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boolean[][] isSum = new boolean[n + 2][sum + 1];
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package com.thealgorithms.dynamicprogramming;
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import org.junit.jupiter.api.Test;
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import static org.junit.jupiter.api.Assertions.*;
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class PartitionProblemTest {
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@Test
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public void testIfSumOfTheArrayIsOdd(){
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assertFalse(PartitionProblem.partition(new int[]{1, 2, 2}));
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}
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@Test
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public void testIfSizeOfTheArrayIsOne(){
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assertFalse(PartitionProblem.partition(new int[]{2}));
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}
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@Test
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public void testIfSumOfTheArrayIsEven1(){
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assertTrue(PartitionProblem.partition(new int[]{1, 2, 3, 6}));
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}
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@Test
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public void testIfSumOfTheArrayIsEven2(){
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assertFalse(PartitionProblem.partition(new int[]{1, 2, 3, 8}));
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}
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}
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